-16x^2+56x+6=0

Solution for -16x^2+56x+6=0 equation:

-16x^2+56x+6=0

a = -16; b = 56; c = +6;
Δ = b2-4ac
Δ = 562-4·(-16)·6
Δ = 3520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3520}=\sqrt{64*55}=\sqrt{64}*\sqrt{55}=8\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(56)-8\sqrt{55}}{2*-16}=\frac{-56-8\sqrt{55}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(56)+8\sqrt{55}}{2*-16}=\frac{-56+8\sqrt{55}}{-32}
$